Quote
RBuster
[...] Voltage is divided which would cause the Amps to double... [...]
If refering to having the motors in wired in series, then coil of first motor becomes in series with same coil of the other motor. Voltage does indeed divide among coils, but the amps do not double. Coils being wired in series its the same current circulating in both. So the amps also decrease, because the current finds it harder to circulate on both parts if they are in series coz their resistance (impedance) adds together forming a bigger value. So voltage divides between coils, and current gets lower (proportionally with the values of both serialized coils added together).
Stepper drivers could handle 2 motors wired with coils in series like that if the coil resistance (impedance) is small enough so when added together it remains "workeable". Basically the driver does not "see" two motors, but sees just one motor with a double coil resistance. First effect, the current will rise slower because of that, which at some extent can be mitigated with higher supply voltage, like using 24v instead of 12v. But otherwise take a look at phase resistance, if its about some motors which have 8 ohms coils, those wont work in series because 8 ohms is already too much, but effectively 16 ohms is well beyond acceptable. On the other hand some motors with coil resistance like 1-2 ohms will form together a resistance like 2-4 ohms which is still good. One note, the steppers are supplied at frequency so in the big picture the impedance counts, but practically its easier to talk and measure Ohms with a multimeter than it is to figure out impedance value at x freq. And coil resistance still matters in rise times, and its still linked good to inductance. In relative terms, a low coil resistance points to a low inductance, usually in same form factor low resistance means thicker wire hence lower turns, and aslo similarly the other way around, same form factor with higher resistance means thin wire and higher number of turns, sort of.